A 92-kg fullback is running at 3.6 m/s to the east and is stopped in 0.85 s by a head-on tackle by a tackler running due west.
a)Calculate the original momentum of the fullback.
Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the momentum is to the east, and negative value if the direction of the momentum is to the west.
b)Calculate the impulse exerted on the fullback.
Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the impulse is to the east, and negative value if the direction of the impulse is to the west.
c)Calculate the impulse exerted on the tackler.
Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the impulse is to the east, and negative value if the direction of the impulse is to the west.
d)Calculate the average force exerted on the tackler.
Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the force is to the east, and negative value if the direction of the force is to the west.

Respuesta :

a) The original momentum of the fullback is 331.2 kgm/s.

b) The impulse exerted on the fullback is - 331.2 kgm/s

c) The impulse exerted on the tackler is 331.2 kgm/s

d) The average force exerted on the tackler is 389.64 N

Given:

Mass of the fullback, m = 92 kg

Initial velocity of the fullback , u = 3.6 m/s

Time of the motion of the fullback , t = 0.85s

The original momentum of the fullback ;

[tex]P_{i} = mv\\P_{i} = (92) (3.6)\\P_{i} = 331.2 kg m/s[/tex]

The impulse exerted on the full-back;

J = ΔP = [tex]m v_f - m v_i[/tex]

J = [tex]m ( v_f - v_i)[/tex]

J = 92 ( 0- 3.6)

J = - 331.2 kgm/s

The impulse exerted on the tackler;

[tex]J _1 = - J _2\\J_2 = - J_1\\J_2 = -( - 331.2)\\J_2 = 331.2 kgm/s[/tex]

The average force exerted on the tackler;

F= Δmv/t

[tex]F =\frac{331.2}{0.85} \\F = 389.64 N[/tex]

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