From the first circuit (see attached), it is correct to state that I₄ = 40mA. See the explanation below.
What is a circuit?
A path that is designed to transport electric current is that is referred to as a circuit.
How do we compute for the missing details?
I = 200mA
= 20mA + 140mA + I₄
I₄ = 200 - 160
I₄ = 40mA
From the above, we can rightly posit:
R₄ = 3/(40x 10⁻³)
= 75 Ω
Hence
V₆ = V₄ - V₅
= 3v - 2v
= 1v
R₆ therefore, =
V₆/I₆
= 1/ (40 x 10 ⁻³)
= 14.28 Ω
I₃ = I₄ + I₆
= 40 + 140
= 180mA
R₃ = 9/(180 x 10⁻³)
= 50Ω
R₂ = 12/20 x (10⁻³)
= 60 Ω
Then,
Vbattery =
200 x 10⁻³ x90
= 18 volts
The above indices is used to complete the image. See Circuit Image II.
Learn more about Circuits:
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