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A bubble of air of volume 1 cm^{3} is released by a deep-sea diver at a depth where the pressure is 4.0 atmospheres. Assuming its temperature remains constant (T1 = T2), what is its volume just before it reaches the surface where the pressure is 1.0 atmosphere?

Respuesta :

The volume of the bubble just before the surface is 4 cm^3.

What is Boyle's law?

  • As per Boyle's law,the volume of a gas at constant temperature varies inversely with the pressure exerted on it.
  • P1V1=P2V2
  • where , P1=pressure at the initial stage

V1=volume of the initial stage

P2= pressure at the final stage

V2= volume at the final stage

How to calculate volume of the bubble just before the surface of water ?

  • P1=4atm, V1=1cm^3, P2=1atm
  • V2=P1V1/P2

=(1×4)/1

=4cm³

Thus , we can conclude that the volume of the bubble just before the surface of water is 4cm³.

Learn more about Boyle's law here:

brainly.com/question/24938688

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