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The aeroplane then continues at a CONSTANT VELOCITY for a further 800 m before leaving the runway. The length of the runway is 2 000 m. 8 m-s-1 1 .2 1.3 → Define the term vector. Convert 67 m-s¹ to km.h¹. 67 m-s¹ Calculate the: .3.1 3.2 1.3.3 3.4 30 s 800 m Acceleration of the aeroplane during the first 30 seconds Distance travelled by the aeroplane during the first 30 seconds Time taken by the aeroplane to travel the 800 m Length of the runway NOT USED when the aeroplane leaves the runway (2) (1 (4 (4 (3​

Respuesta :

  • Acceleration during first 30 seconds = 1.77m[tex]s^{-2}[/tex]
  • Distance travelled during the first 30 seconds = 796.5m
  • Time taken to travel the 800 m = 100 seconds
  • Length of the runway not used = 1200m

  • Vector is a quantity with both direction and magnitude, especially when used to map out where one point in space is in relation to another.
  • Acceleration = s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]

        800 = 0 + [tex]\frac{1}{2}[/tex]a(30)[tex]^{2}[/tex]

        800 = 450a

        a = 1.77m[tex]s^{-2}[/tex]

  • Distance =  s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]

        s = 0+  [tex]\frac{1}{2}[/tex]1.77[tex]t^{2}[/tex]

        s =  [tex]\frac{1}{2}[/tex]1.77(30)[tex]^{2}[/tex]

        s = 796.5m

  • Time taken = distance / velocity

        t = 800/8

        t = 100 sec

  • Length of the runway not used  = total length of runway-total length covered before leaving runway

       2000 -800

      length = 1200m

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