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Suppose you have a right triangle with congruent legs and a hypotenuse that measure (12sqrt(5))/5 What is the length of the smaller leg? Round to the nearest hundredth

Suppose you have a right triangle with congruent legs and a hypotenuse that measure 12sqrt55 What is the length of the smaller leg Round to the nearest hundredt class=

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MrRoyal

The length of the smaller leg is 3.79

How to determine the length of the smaller leg?

Represent the smaller leg with x.

So, we have:

[tex]x^2 + x^2 = ((12\sqrt5)/5)^2[/tex] -- Pythagoras theorem

This gives

2x^2 = 144/5

Divide by 2

x^2 = 72/5

This gives

x^2 = 14.4

Take the square root

x = 3.79

Hence, the length of the smaller leg is 3.79

Read more about right triangles at

https://brainly.com/question/6322314

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