Answer:
-0.10472[tex]\frac{rad}{s}[/tex]
Explanation:
Remember that any clockwise rotation is considered negative, and any counterclockwise rotation is considered positive.
The formula for period is:
[tex]T = \dfrac{2\pi}{\omega}[/tex]
Solve for [tex]\omega\\[/tex] and you get:
[tex]\omega=\dfrac{2\pi}{T}[/tex]
The period is 60 seconds so make that division and you're left with -0.10472[tex]\frac{rad}{s}[/tex] or -0.10[tex]\frac{rad}{s}[/tex] if significant figures apply (negative because the rotation is clockwise).
