[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: equation \: : \:y = 3x - 10[/tex]
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[tex] \large \tt Solution \: : [/tex]
Slope of parallel lines are equal.
[tex] \texttt{Step 1 - Find slope of line -6x + 2y = 4} [/tex]
[tex]\qquad \tt \rightarrow \: - 6x + 2y = 4[/tex]
[tex]\qquad \tt \rightarrow \: 2( - 3 x+ y) = 2(2)[/tex]
[tex]\qquad \tt \rightarrow \: - 3x + y = 2[/tex]
[tex]\qquad \tt \rightarrow \: y = 3x + 2[/tex]
comparison with y = mx + c, m = slope = 3
[tex] \textsf{Step 2 - Use slope and points to find equation} [/tex]
[tex]\qquad \tt \rightarrow \: y - ( - 4) = 3(x - 2)[/tex]
[tex]\qquad \tt \rightarrow \: y + 4 = 3x - 6[/tex]
[tex]\qquad \tt \rightarrow \: y = 3x - 6 - 4[/tex]
[tex]\qquad \tt \rightarrow \: y = 3x - 10[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
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Answer: [tex]\textsf{y = 3x - 10}[/tex]
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Given: [tex]\textsf{Goes through (2, -4) and parallel to -6x + 2y = 4}[/tex]
Find: [tex]\textsf{The equation that follows the criteria provided}[/tex]
Solution: First we need to solve for y in the equation that was provided so we can get the slope. Then we plug in the values into the point-slope formula and then solve for y to get our final equation.
Add 6x to both sides
Divide both sides by 2
Plug in the values
Distribute and simplify
Subtract 4 from both sides
Therefore, the equation that follows the information that was provided in the problem statement is y = 3x - 10.
