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Answer:
(3, 6) and (-3, 18)
Step-by-step explanation:
[tex] {x}^{2} - 2x + 3 = - 2x + 12 \\ \\ {x}^{2} - 9 = 0 \\ \\ (x - 3)(x + 3) = 0 \\ \\ x = \pm3[/tex]
If x = 3, y = -2(3) + 12.
If x = -3, y = -2(-3) + 12 = 18