In the imaged attached, the most precise name for ABCD is known to be rhombus.
What is the shape about?
Looking at the shape attached, one can see that the diagonals of a parallelogram are said to be bisecting one other and if it cross at right angles, it is said to be a rhombus.
Using the Diagonal midpoints of AC and BD, the equation will be:
(A+C)/2
(B+D)/2
To find if the midpoints are similar, then:
A +C = (3, 5) +(6, 2) = (9, 7)
B +D = (7, 6) +(2, 1) = (9, 7)
Therefore, from the solution above, the midpoints of the diagonals are the same, making the shape to be a parallelogram.
In terms of Diagonal vectors, the shape will be perpendicular when the figure is a rhombus. So:
AC = C -A = (6, 2) -(3, 5) = (3, -3)
BD = D -B = (2, 1) -(7, 6) = (-5, -5)
So the lengths will be (3√2 vs 5√2).
Note also that the dot-product of these values need to be zero if they are perpendicular and as such:
AC·BD = x1·x2 +y1·y2 = (3)(-5) +(-3)(-5) = -15 +15 = 0
Therefore, one can say that the diagonals are known to different length and are perpendicular bisectors, so the shape above is regarded as rhombus.
Learn more about shapes from
https://brainly.com/question/27997287
SPJ1
