[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
- [tex]\qquad \tt \rightarrow \: x= 13 \degree[/tex]
- [tex]\qquad \tt \rightarrow \: y= 11 \degree[/tex]
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[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \:( 3y + 5 + 52) + 90 = 180[/tex]
[ Co - interior angles ]
[tex]\qquad \tt \rightarrow \: 3y + 57 + 90 = 180[/tex]
[tex]\qquad \tt \rightarrow \: 3y + 147 = 180[/tex]
[tex]\qquad \tt \rightarrow \: 3y = 180 - 147[/tex]
[tex]\qquad \tt \rightarrow \: 3y = 33[/tex]
[tex]\qquad \tt \rightarrow \: y = \cfrac{33}{3} [/tex]
[tex]\qquad \tt \rightarrow \: y = 11 \degree[/tex]
[tex] \large \tt \: For \: \: x : [/tex]
[tex]\qquad \tt \rightarrow \: 4x= 52[/tex]
[ Alternate interior angles ]
[tex]\qquad \tt \rightarrow \: x= \cfrac{ 52}{4}[/tex]
[tex]\qquad \tt \rightarrow \: x= { 13}{} \degree[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
