In rhombus ABCD , m∠ECD=31∘ .
What is m∠ADE ?
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Answer:
angle ADE=59°
Step-by-step explanation:
ECD=EAD=31°...[Base angles are equal in an isosceles triangle]
[∆ADC is isosceles]
EAD+ECD+ADC= 180°[Angles in a triangle add upto 180°]
so, ADC= 180-(31+31)= 118°
ADE= 118÷2[BD perpendicularly bisects ADC]
=59°
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