answer
From the above equation it is clear that in the combustion of Ethane, 10.5- moles of oxygen is (336 g) required to produce 9- moles of water.
Explanation:
C2H6 + 7/2 O2-----------> 2CO2 + 3H2O
Multipying the above Equation throughout by 3, we get
3 C2H6 + 21/2 O2-------->6 CO2+ 9 H2O
Answer:
C2H6 + 7/2 O2-----------> 2CO2 + 3H2OMultipying the above Equation throughout by 3, we get3 C2H6 + 21/2 O2-------->6 CO2+ 9 H2OFrom the above equation it is clear that in the combustion of Ethane, 10.5- moles of oxygen is (336 g) required to produce 9- moles of water.
