What is the area of Brooke’s swimming pool?

Answer:
Step-by-step explanation:
[tex]A_{trapezoid}[/tex] = [tex]\frac{b_{1} +b_{2} }{2}[/tex] × h
[tex]A_{rectangle}[/tex] = lw
~~~~~~~~~~~~~~
[tex]A_{1}[/tex] = [tex]\frac{12+3}{2}[/tex] × 4 = 30 m²
[tex]A_{2}[/tex] = 10 × ( 10 - 4 ) = 60 m²
[tex]A_{total}[/tex] = [tex]A_{1}[/tex] + [tex]A_{2}[/tex] = 30 + 60 = 90 m²