he image of trapezoid ABCD has coordinates A′(–2, –5), B′(–1, –2), C′(2, –2), and D′(3, –5). It was translated by the rule T–1, –3(x, y). Which diagram shows the pre-image?

Respuesta :

The  pre-image that shows the coordinates A′(–2, –5), B′(–1, –2), C′(2, –2), and D′(3, –5) when translated by the rule T–1, –3(x, y) is the first image on the diagram attached.

What is the rule about?

The rule states that: T–1, –3(x, y)

Therefore:

A =  -2 + 1, -5 + 3 = -1, -2

B = -1 + 1, -2 + 3 = 0, 1

C= 2 + 1,  -2 + 3 = 3, 1

D = 3 + 1, -5 + 3 = 4, 1

Since the rule is x = -1, y =  –3 , therefore, the pre-image will be x¹ + 1, y¹ + 3 and the first image fit into this.

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