Step-by-step explanation:
To get the angle of QPR, we subtract 90-60=30. This proves that the triangle is a 30,60,90, as angle QRP must be 60°. To get the area, we must know the length and width. These can be derived from a known relationship within 30,60,90 triangles.
[tex]qp = \frac{\sqrt{3}}{2} n[/tex]
[tex]qr = \frac{1}{2} n[/tex]
[tex]pr = n[/tex]
because half of pr is 10, we can conclude that n is 20. So we plug 20 into N for QP and QR, and get values of
[tex]qp = 5 \sqrt{3} [/tex]
[tex]qr = 5[/tex]
Now we multiply (l*w)/2 and get:
[tex] \frac{(5 \sqrt{3} \times 5)}{2} = 21.65 \: units[/tex]
