zionknyc
contestada

50 POINTS+brainliest but reposting again because my points were used last time: How do you graph a quadratic equation in vertex form when the equation is a perfect square? Use x² -4x+4 as an example
you will be reported if your answer is absurd

Respuesta :

alexyclu

Answer:

If it is a perfect square, k=0 in the form y=a(x-h)^2+k.

Step-by-step explanation:

x^2-4x+4=(x-2)^2, meaning that the vertex is at the point (2,0).

Hope this helped :)

brendaobregon
Answer:
If it is a perfect square, k=0 in the form
y=a(x-h) ^2+k.
Step-by-step explanation:
x^2-4x+4=(×-2) ^2, meaning that the vertex
is at the point (2,0).

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