Let's take this problem step by step:
To find the ordered pair of the system:
⇒ must set both equations equal to each other
⇒ must solve for 'x'
Let's solve:
[tex]x^2-2x+3=-2x+28\\x^2-2x+3+2x-28=0\\x^2-25=0\\(x-5)(x+5)=0[/tex]
Let's find the x-values:
[tex](x-5)=0\\x=5\\\\(x+5)=0\\x=-5[/tex]
Let's find f(x)'s value for each of the 'x':
[tex]x=5\\f(5)=-2(5)+28=18\\\\x=-5\\f(-5)=-2(-5)+28=38[/tex]
Answer: (5, 18), (-5,38)
Hope that helps!
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