In the given figure, lines AC and BD intersect each other at point E.
If ∠AEB:∠BEC = 9 : 11, find all the angles.

The value of the angle AED = 99 degree , Angle BEC is 99 degree , angle DEC = 81 degree , angle AEB is 81 degree
The straight line has an angle of 180 degree.
The two lines AC and BD intersects such that
∠AEB:∠BEC = 9 : 11
Let angle BEC be x
Then
Angle AEB is 9x/11
and angle AEC + BEC = 180 degree
(9x/11) + x = 180
9x +11x = 11 * 180
20x = 11 * 180
x = 99 degree
Angle BEC is 99 degree
and angle AEB is 81 degree
As Angle AED is vertically opposite to angle BEC
Therefore angle AED = 99 degree
As Angle DEC is vertically opposite to angle AEB
Therefore angle DEC = 81 degree.
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