PLEASE HELP ASAP!!!!
What is the rectangular equivalence to the parametric equations?

x(θ)=3cosθ+2,y(θ)=2sinθ−1 , where 0≤θ<2π .

Drag a term into each box to correctly complete the rectangular equation.
____ + ________ = 1, where the x is on the interval _______

options:
(x-2)^2/9
(x+2)^2/9
(x-1)^2/4
(x+1)^2/4
(y-2)^2/9
(y+2)^2/9
(y-1)^2/4
(y+1)^2/4
[-3,3]
[-3,1]
[-2,2]
[-1,5]

Respuesta :

The correct answer is option A [tex](\dfrac{x-2}{3})^2+(\dfrac{y+1}{2})^2=1[/tex] it will be an ellipse.

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Let's consider the following trigonometric identity:

Sin²[tex]\theta[/tex] + Cos²[tex]\theta[/tex] = 1

Each trigonometric function is cleared respectively in given parametric equations:

[tex]Cos \theta = \dfrac{x-2}{3}[/tex] and  [tex]Sin\theta =\dfrac{y+1}{2}[/tex]

The equivalent expression in rectangular form is:

[tex](\dfrac{x-2}{3})^2+(\dfrac{y+1}{2}^)^2 = 1[/tex]

Therefore the correct answer is option A [tex](\dfrac{x-2}{3})^2+(\dfrac{y+1}{2})^2=1[/tex] it will be an ellipse.

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