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Five resistors each have resistance R. Three of the resistors are connected in series and this combination is then connected in parallel with the two other resistors which have been connected in series with each other. What is the equivalent resistance for this arrangement

Respuesta :

Answer:

6/5  * R

Explanation:

The 3 in series sum to 3R for one branch of the parallel circuit

 the 2 in series sum to 2R  for the other side of the parallel circuit

now find the equivalent R of the parallel circuit with 3R and 2R

 here is one way

   Requiv = 1 / ( 1/(3R) + 1/(2R) ) =

                  1/ ( 5/(6R) ) =

                    6R/5  

the equiv resistance = 6/5  * R