urgent help needed algebra 2

The missing values are shown in the attached picture, and 41 degrees F = 5 degrees C.
It is defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.
We have:
[tex]\rm F = \dfrac{9}{5}C + 32[/tex]
Make subject C and solve:
[tex]\rm \dfrac{5}{9}(F-32) = \dfrac{5}{9}\times\dfrac{9}{5}C[/tex]
[tex]\rm \dfrac{5}{9}(F-32) = C[/tex]
Plug F = 41
[tex]\rm \dfrac{5}{9}(41-32) = C[/tex]
[tex]\rm \dfrac{5}{9}(9) = C[/tex]
41 degrees F = 5 degrees C
Thus, the missing values are shown in the attached picture, and 41 degrees F = 5 degrees C.
Learn more about the unit conversion here:
brainly.com/question/14350438
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