Answer:
-6, 14, -26, 10x -4, -8x + -2x - 6
Step-by-step explanation:
So F(x) is setting that the values before the lines are equal to x and should be applied to the problem. Dont forget PEMDAS with these tho, they'll try to trick u like that.
So for the first one, f(0) you plug 0 where the x's are.
1.) 8(0)^2 +2(0) -6
0 + 0 - 6 = -6
2.) 8(2) +2(2) - 6
16+ 4-6= 20 - 6= 14
3.) 8(-2) + 2(-2) -6
-16 + -4 -6 = -26
On the ones where they leave the x there, you just have to leave the x. But don't forget distribution tho.
4.) 8(x+1) +2(x+1) -6
8x +8 + 2x + 2 -6
10x +10 -6 = 10x -4
5.) 8(-x) + 2(-x) -6
-8x + -2x -6
