For a physics experiment, a solid cube is suspended from a spring scale. The gravitational force exerted on the cube is 0.714 N as measured when the object is suspended from a spring scale. When the suspended cube is submerged in water (ρ = 1000 kg/m3), the scale reads 0.450 N. What is the side of this cube in cm

Respuesta :

The side of this cube will be 2.9996 cm. The net force on the solid cube is acting upward.

What is buoyancy force?

A fluid exerts an upward force against the weight of a partly or completely submerged item. The weight of the overlying fluid causes pressure to rise with depth in a column of fluid.

Given data;

Actual weight.W=0.714 N

Apparent weight,W'=0.450 N

The density of water,ρ=1000 kg/m³

The net force on the solid cube is;

Apparent weight = actual weight - buoyancy force

Buoyancy force = Actual weight - apparent weight

F=W-W'

F = 0.714 - 0.450

F= 0.264 N

The buoyancy force(F) is found as;

F = ρgV

0.264 = 1000 × 9.81 × V

V=2.69 × 10⁺⁵

The volume of a cube is found as;

V=a³

2.69 × 10⁺⁵ m³=a³

a=0.02996 m

As we know that 1 m = 100 cm

a=2.996 cm

Hence, the side of this cube will be 2.9996 cm.

To learn more about the buoyancy force refer to the link;

https://brainly.com/question/132673

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