The mass of the hydrogen gas in tank, given the data is 6.17 Kg
PV = znRT
Divid both sides by zRT
n = PV / zRT
but
mole (n) = mass (m) / molar mass (M)
Thus,
m / M = PV / zRT
m = MPV / zRT
m = (2.016 × 493.4615 × 220) / (1.45 × 0.0821 × 298)
m = 6169 g
Divide by 1000 to express in Kg
m = 6169 / 1000
m = 6.17 Kg
Complete question
A gaseous hydrogen stored at 500 Bar and 25°C in a composite storage with an internal volume of 220 liters. Determine the mass of the hydrogen in the tank. Use a compressibility factor Z = 1.45
3.06 kg
6.17 kg.
13.0 kg
5.05 kg
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