The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²
The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;
[tex]B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}[/tex]
where;
m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)
m = 1.2 Am²
The complete question is below:
What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.
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