For the form [tex]y = a(x-h)^2 + k[/tex], the vertex has coordinates (h, k). The vertex is found by (x, y).
If a quadratic equation is written in the form
[tex]y=a(x-h)^2 + k[/tex]
then it is called to be in vertex form.
It is called so because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)
First of all, we used this vertex formula thing since it is visible that there are quadratic functions.
Otherwise, you had to use calculus to get critical points, then a second derivative of functions to find the character of critical points as minima or maxima or saddle, etc to get the location of vertex point.
This point (h,k) is called the vertex of the parabola that the quadratic equation represents.
For the form
[tex]y = a(x-h)^2 + k[/tex], the vertex has coordinates (h, k)
Thus, for the obtained form, we get the coordinates of the vertex as:
[tex]h = -b/2a,, \\ k = c - a\times(b/2a)^2[/tex]
Thus, the coordinates of vertex of [tex]y = ax^2 + bx + c[/tex]is:
[tex](h,k) = (-b/2a, c - a \times (b/2a)^2 )[/tex]
Learn more about the vertex form of a quadratic equation here:
https://brainly.com/question/9912128
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