what is the exact value of [tex]\frac{cos(tan^{-1} (-1)) }{sin(cos^{-1}(\frac{\sqrt{3}}{2}))}[/tex]
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[tex]\frac{cos(tan^{-1} (-1)) }{sin(cos^{-1}(\frac{\sqrt{3}}{2}))}[/tex] =

Respuesta :

We have

arctan(-1) = -π/4

cos(-π/4) = 1/√2

and

arccos(√3/2) = π//6

sin(π/6) = 1/2

Then

cos(arctan(-1)) / sin(arccos(√3/2)) = (1/√2) / (1/2) = √2