original equation
[tex]2y-x=8\\-3x+2y=-12\\[/tex]
line up your terms
[tex]2y-x=8\\\\2y-3x=-12[/tex]
since they are both positive, subtract
[tex]2x=20[/tex]
solve for x
[tex]x=10[/tex]
substitute into one of the equations and solve for y
[tex]2y-(10)=8\\\\2y=18\\\\y=9[/tex]
verify
[tex]2(9)-(10)=8\\\\18-10=9\\\\8=8\\\\LS=RS[/tex]
[tex]-3(10)+2(9)=-12\\\\-30+18=-12\\\\-12=-12\\\\LS=RS[/tex]
