Respuesta :
Note that:
- Marissa= [tex]x + 3 [/tex]
- Older brother= 18
- Younger brother= [tex]\frac {18}{2} [/tex]
To find:
The age of Marissa and her younger brother.
Solution:
Younger brother:
We know that the older brother's age is 18 and he is twice older than the younger brother.
Let the unknown be "x"
[tex] x=\frac{18}{2} [/tex]
[tex]\large\boxed{\sf{x=9 \: years}}[/tex]
Marissa:
Now, we know that the younger brother's age is 9 and Marissa is 3 years older than him.
Let the unknown be "x"
[tex]x=9 + 3[/tex]
[tex]\large\boxed{\sf{x=12 \: years}}[/tex]
Therefore, Marissa is 12 and her younger brother is 9
Answer:
Marissa's age = 12
Younger brother's age = 9
Step-by-step explanation:
Let age of Marissa be x, and her younger brother's y.
Equations formed :
- x = y + 3
- 2y = 18
Finding age of younger brother using Equation 2 :
⇒ 2y = 18
⇒ 2y/2 = 18/2
⇒ y = 9 years old
Substituting y in Equation 1 :
⇒ x = y + 3
⇒ x = 9 + 3
⇒ x = 12 years old
Marissa's age = 12
Younger brother's age = 9
