Respuesta :
Answer:
the radius of the smaller circle = 3√3.
Step-by-step explanation:
let C' be the bigger circle
and C be the smaller circle and r its radius.
Area(C') = π × (9² - r²)
Area(C) = π × r²
Area(shaded region) = area(C') - area(C)
= π × (9² - r²)
the statement “the area of the shaded region is twice that of the smaller circle ” means π × (9² - r²) = 2 × π × r²
Now, let’s solve the equation:
π × (9² - r²) = 2 × π × r²
⇔ π × (9² - r² - 2r²) = 0
⇔ π × (81 - 3r²) = 0
⇔ 81 - 3r² = 0
⇔ 81 = 3r²
⇔ r² = 27
⇔ r = √27
⇔ r = 3√3

Answer:
6.32
Step-by-step explanation:
Area of bigger circle = π(9)² = 81π cm²
Area of smaller circle = π(9)²/2 = 81π/2 = 40.5πcm²
Area scale factor = (Linear Scale factor)²
81π/40.5π = 9²/x² {cancel the π}
81/40.5 = 81/x² (cross multiplication)
81x² = 40.5 × 81
√x² = √40.5 (square root both sides)
x = 6.32