From the calculations and the data provided in the question, the required temperature is 380 K.
The Clasius Clapeyron equation is used to obtain the vapor pressure of a substance at two different temperatures.
Hence;
lnP2/P1 = -ΔHvap/R(1/T2 - 1/T1)
ln(145/1) = -40.7 * 10^3/8.314(1/T2 - 1/273)
4.977 = -(4811)(1/T2 - 1/273)
4.977/-(4811) = (1/T2 - 1/273)
-0.00103 = 1/T2 - 1/273
-0.00103 + 1/273 = 1/T2
0.002633 =1/T2
T2 = 380 K
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