Respuesta :
Area of 16inch pizza = (pi) r^2 = 64pi
Area of 12 inch pizza = (pi) r^2 = 36pi
Jane ate 3 slices of 12" pizza = 3/8 × 36 = 13.5pi
Mark ate 3 slices of 16" pizza = 3/8×64 = 24pi
Difference Mark ate than Jane = 24-13.5 = 10.5pi (sq inches)
Area of 12 inch pizza = (pi) r^2 = 36pi
Jane ate 3 slices of 12" pizza = 3/8 × 36 = 13.5pi
Mark ate 3 slices of 16" pizza = 3/8×64 = 24pi
Difference Mark ate than Jane = 24-13.5 = 10.5pi (sq inches)
They both ate 3/8 of a pizza. Therefore, the quantity that Mark ate in excess of Jane is simply 3/8 × the difference in total area of the pizzas. The 16'' pizza has 64π area, and the 12'' pizza has 36π area, making for a difference of 28π. 3/8 × 28π = 21/2π = 10.5π