The number of moles of water are needed in order to produce 21.8 g of
calcium hydroxide is 0.588 moles.
Moles of any substance will be calculated as:
n = W/M, where
W = given mass
M = molar mass
Given chemical reaction is:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
Moles of 21.8g of Ca(OH)₂ = 21.8g / 74.1g/mol = 0.294mol
From the stoichiometry of the reaction, it is clear that
1 mole of Ca(OH)₂ = needed 2 moles of water
0.294 mole of Ca(OH)₂ = needed 2×0.294=0.588 moles of water
Hence required moles of water is 0.588 moles.
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