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Which describes how to graph g(x) = 3√x-5+7 by transforming the parent function?

Translate the parent function 5 units to the left and 7 units up.
Translate the parent function 5 units to the right and 7 units up.
Translate the parent function 5 units down and 7 units to the right.
Translate the parent function 5 units up and 7 units to the right.

Respuesta :

assuming
[tex]g(x)=3 \sqrt{x-5}+7 [/tex]
and parent function is [tex]3 \sqrt{x} [/tex]


to move a function up c units, add c to whole function
to move a function to right c units, minus c from every x

7 was added to whole function and 5was mnused from every x

moved 7 up and 5 to right

2nd option

Answer:

Option 2 -Translate the parent function 5 units to the right and 7 units up.

Step-by-step explanation:

Given : Function [tex]g(x) = 3\sqrt{x-5}+7[/tex]

To find : Which describes how to graph  [tex]g(x) = 3\sqrt{x-5}+7[/tex] by transforming the parent function?

Solution:

First we look the parent function of g(x)

The parent function of g(x) is [tex]3\sqrt{x}[/tex]

Now, we see the transformations,

In [tex]g(x) = 3\sqrt{x-5}+7[/tex]

7 unit is added in the function i.e,

If f(x)→f(x)+a then function is shifted upward by unit a

⇒ g(x)→g(x)+7 then function is shifted upward by unit 7

5 unit is subtracted in the value of x

If f(x)→f(x-b) then function is shifted right by unit b

⇒ g(x))→g(x-5) then function is shifted right by unit 5

Therefore, The translation in the parent function is 5 units right and 7 unit upward.

So,Option 2 is correct.