Respuesta :
if one of the charge is doubled, the electric potential energy would be doubled too
Coulomb's Law :
Force = K(q1q2/r^2)
K = constant
q1 = charge 1
q2 = charge 2
r = radius
If the charge of the particles are same then,
q1= 1
q2=1
r=2 (consider /by default)
F = (1)(1)/(2)^2 = 0.25
If charge is the only variable, then the force will be ½ the original force. If the charge on one particle (q) is increased by a factor of 2. For example...
q1 = 2
q2 = 1
r = 2(by default)
F = (2)(1)/(2)^2 = 0.5
0.25 < 0.5 , the electric force get increased by the factor of 2.
What is electric force ?
“The attractive or repulsive interaction between any two charged objects is an electric force.”
What is Coulombs law ?
“Coulombs law states that like charges repel and opposite charges attract, with a force proportional to the product of the charges and inversely proportional to the square of the distance between them”.
Know more about electric force here
https://brainly.com/question/2526815
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