Respuesta :
The statement (p and (p => q)) => q) is not a contingency because of it evaluating to only true while a contingency statement includes both true values and some false values.
What is a contingency statement?
Contingency is a statement in which there are some true and some false values for every value of its propositional variables.
The statement given is (p and (p => q)) => q), or in more symbolic way, it is: ((p ∧ (p → q)) → q)
Now, let we evaluate it for p = False, and q = False.
Then we get:
(p → q) = T (as False implied False)
Now, (p ∧ (p → q)) is F and T which is F
Then, ((p ∧ (p → q)) → q) is F → F which is True, or T.
Thus, p = F,and q = F makes ((p ∧ (p → q)) → q) = T
Similarly, the truth table for the statement (p and (p => q)) => q) or simply ((p ∧ (p → q)) → q) is:
p q ((p ∧ (p → q)) → q)
F F T
F T T
T F T
T T T
Since all the values are true, thus, this isn't a contingency.
Thus, the statement (p and (p => q)) => q) is not a contingency because of it evaluating to only true while a contingency statement includes both true values and some false values.
Learn more about contingency here:
https://brainly.com/question/11656774
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