The approximate solutions for x when f(x) = 0 are -0.25, -1.86, and 2.11.
The given function is:
f(x)=x^3-4x-1
What is the solution to an equation?
The solution to an equation is the point where the function value becomes zero.
As we know when f(a).f(b) <0, the root lies in between a and b.
f(-1) = 2
f(0) = -1
f(-1).f(0) = -2
So a solution will lie in between (-1,0).
Similarly,
f(-3) = -ve
f(-2)= -ve
No solution in between -3 and -2
f(-2) = -ve
f(-1) = +ve
One solution in between -2 and -1 i.e. -1.86
f(0) = -ve
f(1) = -ve
No solution in between 0 and 1
f(1) = -ve
f(2) = -ve
No solution in between 1 and 2.
f(2) = -ve
f(3) = +ve
One solution in between 2 and 3 i.e. 2.11
Therefore, the approximate solutions for x are -0.25, -1.86, and 2.11.
