Respuesta :

LammettHash
[tex]x=2+3\sin t\implies x-2=3\sin t[/tex]
[tex]y=-3-3\cos t\implies y+3=-3\cos t[/tex]

Recall that [tex](\pm a\sin t)^2+(\pm a\cos t)^2=a^2[/tex]. This means

[tex](3\sin t)^2+(-3\cos t)^2=(x-2)^2+(y+3)^2=9[/tex]

and so the parameter is eliminated.

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