Respuesta :
hint: [tex]\bf \begin{cases}
m+n=5\to &m=\boxed{5-n}
\\ \quad \\ \quad \\
m-n=3\to &\boxed{5-n}-n=3\quad \impliedby \textit{solve for "n"}
\end{cases}[/tex]
The value of m and n is 4 and 1. The solution is (4,1). Option A is correct.
The given system of equations is,
[tex]m+n=5\\m-n=3[/tex]
It is required to solve the equations using the substitution method.
So, use the first equation to get the value of n and substitute it in the second equation as,
[tex]m+n=5\\n=5-m\\m-n=3\\m-(5-m)=3\\2m-5=3\\2m=8\\m=4\\n=5-n=5-4\\n=1[/tex]
Therefore, the value of m and n is 4 and 1. The solution is (4,1). Option A is correct.
For more details, refer to the link:
https://brainly.com/question/8409825