Respuesta :
The coordinates of the center of this circle will be the average between the extreme points
C = ( (xo+x1)/2 , (yo+y1)/2)
Where,
xo = 3 and x1 = 9
yo = 8 and y1 = 16
Then us stay with"
C = ( (3+9)/2 , (8+16)/2)
C = ( 12/2 , 24/2)
C = ( 6 , 12 )
C = ( (xo+x1)/2 , (yo+y1)/2)
Where,
xo = 3 and x1 = 9
yo = 8 and y1 = 16
Then us stay with"
C = ( (3+9)/2 , (8+16)/2)
C = ( 12/2 , 24/2)
C = ( 6 , 12 )
The coordinates of the center of a circle is (6,12)
Center
The coordinates of the center of a circle is halfway between the endpoints of the diameter
The endpoints of the diameter is given are:
(3,8) and (9,16)
Midpoint
The midpoint (M) of two points is calculated as:
[tex]M = \frac{1}{2} \times (x_1 + x_2, y_1 + y_2)[/tex]
So, we have:
[tex]M = \frac{1}{2} \times (3+ 9, 8+ 16)[/tex]
[tex]M = \frac{1}{2} \times (12, 24)[/tex]
Expand the above equation
[tex]M = (\frac{1}{2} \times 12, \frac{1}{2} \times 24)[/tex]
[tex]M =(6,12)[/tex]
Hence, the coordinates of the center is (6,12)
Read more about midpoints at:
https://brainly.com/question/16828532