The endpoints of the diameter of a circle have the coordinates (3, 8) and (9, 16).
 
What are the coordinates of the center of the circle?

Respuesta :

The coordinates of the center of this circle will be the average between the extreme points


C = ( (xo+x1)/2 , (yo+y1)/2)

Where,

xo = 3 and x1 = 9

yo = 8 and y1 = 16

Then us stay with"


C = ( (3+9)/2 , (8+16)/2)

C = ( 12/2 , 24/2)

C = ( 6 , 12 )


The coordinates of the center of a circle is (6,12)

Center

The coordinates of the center of a circle is halfway between the endpoints of the diameter

The endpoints of the diameter is given are:

(3,8) and (9,16)

Midpoint

The midpoint (M) of two points is calculated as:

[tex]M = \frac{1}{2} \times (x_1 + x_2, y_1 + y_2)[/tex]

So, we have:

[tex]M = \frac{1}{2} \times (3+ 9, 8+ 16)[/tex]

[tex]M = \frac{1}{2} \times (12, 24)[/tex]

Expand the above equation

[tex]M = (\frac{1}{2} \times 12, \frac{1}{2} \times 24)[/tex]

[tex]M =(6,12)[/tex]

Hence, the coordinates of the center is (6,12)

Read more about midpoints at:

https://brainly.com/question/16828532