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In the following reaction, how many grams of ammonia (NH3) will react with 27.8 grams of nitric oxide (NO)? 4NH3 + 6NO → 5N2 + 6H2O The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.

a- 23.7 grams

b- 10.5 grams

c- 73.5 grams

d- 32.7 grams

Respuesta :

JoshEast
4NH₃ + 6NO → 5N₂ + 6H₂O

mol of NO  =  [tex] \frac{mass of NO}{Molar Mass of NO} [/tex]
 
                  =  [tex] \frac{27.8 g}{30.01 g / mol} [/tex]
                   
                  =  0.93 mol

Based on the balance equation mole ratio of NH₃  :  NO  is   4 : 6
                                                                                            =  2 : 3

If mol  of NO  =  0.93 mol

then mol of NH₃ = [tex] \frac{0.93 mol * 2}{3} [/tex]
                           
                          =  0.62 mol

Mass of ammonia =  mol  ×  molar mass
          
                             =  0.62 mol   ×  17.03 g/mol
 
                             =  10.54 g

Therefore B is the best answer
the anwser is b10.5g

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