Answer:
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Step-by-step explanation:
- This is Right Angled Triangle.
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We'll solve this using the Pythagorean Theorem.
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Let,
- x be BC, where BC is the Perpendicular.
- 8 be AB, where AB is the Base.
- 9 be AC, where AC is the Hypotenuse.
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We know that,
[tex]{ \longrightarrow \pmb{\qquad \: (AB) {}^{2} +( BC) {}^{2} = (AC) {}^{2} }}[/tex]
[tex]{ \longrightarrow \sf \qquad \: (8) {}^{2} +( x) {}^{2} = (9) {}^{2} } [/tex]
[tex]{ \longrightarrow \sf \qquad \: ( x) {}^{2} = (9) {}^{2} - (8) {}^{2}} [/tex]
[tex]{ \longrightarrow \sf \qquad \: ( x) {}^{2} = 81 - 64} [/tex]
[tex]{ \longrightarrow \sf \qquad \: ( x) {}^{2} = 17} [/tex]
[tex]{ \longrightarrow \it \qquad \pmb {x = \sqrt{17 \: \: } } }[/tex]
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Therefore,
