[tex] \qquad \qquad\qquad\large\overbrace{\underbrace{\underline{ \boxed{ \sf \:Aƞsweɾ }}}}[/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \: 5(4 - 3x) = - 10[/tex]
[tex]\qquad \sf \dashrightarrow \: 20- 15x = - 10[/tex]
[tex]\qquad \sf \dashrightarrow \: - 15x = - 10 - 20[/tex]
[tex]\qquad \sf \dashrightarrow \: - 15x = - 30[/tex]
[tex]\qquad \sf \dashrightarrow \: x = - 30 \div ( - 15)[/tex]
[tex]\qquad \sf \dashrightarrow \: x = 2[/tex]
Therefore, the value of x is 2
