The geometric series would have a uniform common ratio
The recursive definition of the geometric sequence is [tex]a_n = 4a_{n-1}[/tex] where a1 = 128
Assume the geometric sequence is given as:
128,32,8,2
And the question requires the recursive definition of the geometric series
Start by calculating the common ratio (r)
[tex]r = \frac{a_{n}}{a_{n-1}}[/tex]
Substitute 2 for n
[tex]r = \frac{a_2}{a_1}[/tex]
Substitute known values
[tex]r = \frac{128}{32}[/tex]
Evaluate the quotient
[tex]r = 4[/tex]
Substitute 4 for r in [tex]r = \frac{a_{n}}{a_{n-1}}[/tex]
[tex]4 = \frac{a_{n}}{a_{n-1}}[/tex]
Cross multiply
[tex]a_n = 4a_{n-1}[/tex]
Hence, the recursive definition of the geometric series is [tex]a_n = 4a_{n-1}[/tex] where a1 = 128
Read more about geometric sequence at:
https://brainly.com/question/24643676
