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A proton is moving south with a speed of 4500 m/s in a magnetic field of 5500 T directed into the page. Determine the magnitude and direction of the magnetic force on the charge.

a.3.96 x 10-12 N west
b.1.55 x 1026 west
c.1.55 x 1026 east
d.3.96 x 10-12 N east

Respuesta :

Answer:

F = q V X B

V is south and B is into the page

The resultant vector is directed to the East

F = 1.6E-19 * 4.5E3 * 5.5E3 N = 3.96 N East

(Note q is negative for an electron producing a force in the opposite direction)

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