The mass, in grams, of 5.2 x 10^28 atoms of manganese would be 0.0006833 grams
Mass calculation
According to Avogadro, 1 mole of any substance contains 6.022 x [tex]10^{23}[/tex] atoms.
Thus, how many moles would be in 5.2 x [tex]10^{28}[/tex]atoms of Mn:
= 6.022 x [tex]10^{23}[/tex] /1 x 5.2 x [tex]10^{28}[/tex]
= 0.00001158 moles
Mass of 0.00001158 moles Mn = 0.00001158 x 54.9
= 0.0006833 grams
More on Avogadro's constant can be found here: https://brainly.com/question/21177668
