Write a quadratic function in standard form that passes through (5,0), (9,0), and (7, -20). {Use " ^ " to make your exponent by holding the left shift key and hit the #6 key} Show your work in support of your answer. *

Respuesta :

By using the roots and the given point, we conclude that the quadratic equation is:

y = 5*(x - 5)*(x - 9).

How to get the quadratic equation?

We know that if a quadratic has a leading coefficient a, and the roots x₁ and x₂, we can write it as:

y = a*(x - x₁)*(x - x₂).

In this case, we know that it passes through the points (5, 0) and (9, 0), then we conclude that the quadratic equation is:

y = a*(x - 5)*(x - 9).

Now, we also know that the equation passes through (7, - 20), then we have that:

-20 = a*(7 - 5)*(7 - 9)

-20 = a*(2)*(-2) = a*-4

-20/-4 = a  = 5

The quadratic equation is:

y = 5*(x - 5)*(x - 9)

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