Respuesta :
a. The equivalent resistance in series is 14.92 µΩ
b. The equivalent resistance in parallel is 2.58 µΩ
Equivalent resistance
There are two types of equivalent resistance
- equivalent resistance in series
- equivalent resistance in parallel
a. Equivalent resistance in series
The equivalent resistance in series is 14.92 µΩ
For a series circuit of two resistors R₁ and R₂, the equivalent resistance in series is R = R₁ + R₂
Since R₁ = 3.32 µΩ and R₂ = 11.6 µΩ
So, R = R₁ + R₂
R = 3.32 µΩ + 11.6 µΩ
R = 14.92 µΩ
So, the equivalent resistance in series is 14.92 µΩ
b. Equivalent resistance in parallel
The equivalent resistance in parallel is 2.58 µΩ
For a series circuit of two resistors R₁ and R₂, the equivalent resistance in parallel is thus 1/R = 1/R₁ + 1/R₂.
Thus R = R₁R₂/(R₁ + R₂)
Since R₁ = 3.32 µΩ and R₂ = 11.6 µΩ
So, R = R₁R₂/(R₁ + R₂)
R = 3.32 µΩ × 11.6 µΩ/(3.32 µΩ + 11.6 µΩ)
R = 38.512µΩ²/14.92 µΩ
R = 2.58µΩ
So, the equivalent resistance in parallel is 2.58 µΩ
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