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A certain space heater that is connected across 220 V and dissipates 1477 W of power in the form of electromagnetic radiation. What is the resistance of the heater?

Respuesta :

leena

Hi there!

We can use the power equation:
[tex]P = \frac{V^2}{R}[/tex]

P = Power (W)
V = Potential Difference (V)
R = Resistance (Ω)

Rearrange to solve for Resistance:
[tex]R = \frac{V^2}{P} = \frac{220^2}{1477} = \boxed{32.769 \Omega}[/tex]

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