Answer:
H+ = 0.001
Step-by-step explanation:
3 = -log[H+]
Identity to use: [tex]-log_{b}(a) = log_{b}(1/a)[/tex]
3 = log[ 1 / H+ ]
Identity to use: [tex]10^{log(x)} = x[/tex]
Therefore, I am going raise each side of the equation to the power of 10 to isolate [ 1 / H+ ]
10³ = [tex]10^{log(\frac{1}{H+} )}[/tex]
1000 = 1 / H+
H+ = 1 / 1000
Answer: H+ = 0.001
